Limits Concept
Grade 12 · Calculus · Worksheet 1
- From graph: as x→7, f(x)→? Answer: ______________
- A particle moves along a curve with its position function given by f(x) = (x^3 - 8)/(x^2 - 4) for x ≠ 2. Determine the limit of f(x) as x approaches 2, which represents the instantaneous position the particle would approach at that moment. Answer: ______________
- lim(x→∞) (3x² + 2x - 1)/(2x² - x + 5) = ? Answer: ______________
- From graph: as x→10, f(x)→? Answer: ______________
- From the table:
x: 3.9, 3.99, 3.999, 4.001, 4.01, 4.1
f(x): 7.8, 7.98, 7.998, 8.002, 8.02, 8.2
lim(x→4) f(x) = ? Answer: ______________
- A pharmaceutical company is modeling the concentration of a new medication in the bloodstream over time. The concentration function is given by C(t) = (3t^2 - 12) / (t^2 - 4) for t > 2 hours. As time continues indefinitely, what value does the drug concentration approach in the bloodstream? Answer: ______________
- Aroha is tracking the temperature of a cooling liquid in a physics experiment. She records the temperature T(t) in degrees Celsius at various times t (in minutes) using the function T(t) = (t^3 - 27)/(t - 3). The function is undefined at exactly t = 3 minutes. Using the table of values below, determine what temperature the liquid approaches as time gets closer and closer to 3 minutes.
t (minutes) | T(t) (°C)
2.9 | 26.11
2.99 | 26.9101
2.999 | 26.991001
3.001 | 27.009001
3.01 | 27.0901
3.1 | 27.91 Answer: ______________
- From the table:
x: 0.96, 0.98, 0.99, 1.00, 1.01, 1.02, 1.04
f(x): 2.81, 2.91, 2.96, undefined, 3.06, 3.11, 3.21
What is lim(x→1) f(x)? Answer: ______________
Answer Key & Explanations
Limits Concept · Grade 12 · Worksheet 1
- From graph: as x→7, f(x)→? Answer: 5 Solution: Look at the graph and find the point where x approaches 7. Check the y-values as x approaches 7 from the left (x = 6.9, 6.99, 6.999). The y-values get closer to 5.
Full step-by-step solution
Step 1: Look at the graph and find the point where x approaches 7.
Step 2: Check the y-values as x approaches 7 from the left (x = 6.9, 6.99, 6.999). The y-values get closer to 5.
Step 3: Check the y-values as x approaches 7 from the right (x = 7.1, 7.01, 7.001). The y-values also get closer to 5.
Step 4: Since the y-values approach 5 from both sides, the limit is 5.
The answer is 5.
- A particle moves along a curve with its position function given by f(x) = (x^3 - 8)/(x^2 - 4) for x ≠ 2. Determine the limit of f(x) as x approaches 2, which represents the instantaneous position the particle would approach at that moment. Answer: 3 Solution: Write the original function: f(x) = (x^3 - 8)/(x^2 - 4) Factor the numerator using difference of cubes: x^3 - 8 = (x - 2)(x^2 + 2x + 4) Factor the denominator using difference of squares: x^2 - 4 = (x - 2)(x + 2) Simplify by canceling the common factor (x - 2): f(x) = (x^2 + 2x + 4)/(x + 2) Now…
Full step-by-step solution
Step 1: Write the original function: f(x) = (x^3 - 8)/(x^2 - 4)
Step 2: Factor the numerator using difference of cubes: x^3 - 8 = (x - 2)(x^2 + 2x + 4)
Step 3: Factor the denominator using difference of squares: x^2 - 4 = (x - 2)(x + 2)
Step 4: Simplify by canceling the common factor (x - 2): f(x) = (x^2 + 2x + 4)/(x + 2)
Step 5: Now take the limit as x approaches 2: lim(x→2) (x^2 + 2x + 4)/(x + 2)
Step 6: Substitute x = 2 into the simplified expression: (2^2 + 2×2 + 4)/(2 + 2) = (4 + 4 + 4)/4 = 12/4 = 3
The answer is 3.
- lim(x→∞) (3x² + 2x - 1)/(2x² - x + 5) = ? Answer: 3/2 Solution: To find the limit as x approaches infinity of (3x² + 2x - 1)/(2x² - x + 5), we follow these steps: Identify the highest power of x in the denominator. The denominator is 2x² - x + 5. The highest power of x here is x².
Full step-by-step solution
To find the limit as x approaches infinity of (3x² + 2x - 1)/(2x² - x + 5), we follow these steps:
Step 1: Identify the highest power of x in the denominator.
The denominator is 2x² - x + 5. The highest power of x here is x².
Step 2: Divide every term in the numerator and the denominator by x².
This is the standard method for limits at infinity of rational functions (polynomial divided by polynomial). We divide each term by x².
Numerator: (3x²)/x² + (2x)/x² - (1)/x² = 3 + 2/x - 1/x²
Denominator: (2x²)/x² - (x)/x² + (5)/x² = 2 - 1/x + 5/x²
So the function becomes: (3 + 2/x - 1/x²) / (2 - 1/x + 5/x²)
Step 3: Take the limit as x approaches infinity.
As x becomes very large (approaches infinity), any term with x in the denominator approaches zero.
Specifically:
2/x approaches 0
1/x² approaches 0
1/x approaches 0
5/x² approaches 0
Step 4: Substitute these limiting values into the expression.
The expression becomes: (3 + 0 - 0) / (2 - 0 + 0) = 3/2
Step 5: State the final answer.
Therefore, the limit is 3/2.
This makes sense because for large values of x, the highest degree terms dominate the behavior of the polynomials. The ratio of the leading coefficients (3 from numerator and 2 from denominator) gives us the limit.
- From graph: as x→10, f(x)→? Answer: 7 Solution: Look at the graph of f(x) as x approaches 10 from the left side As x gets closer to 10 from values like 9.5, 9.8, 9.9, the y-values approach 7 Look at the graph of f(x) as x approaches 10 from the right side As x gets closer to 10 from values like 10.5, 10.2, 10.1, the y-values also approach 7…
Full step-by-step solution
Step 1: Look at the graph of f(x) as x approaches 10 from the left side
Step 2: As x gets closer to 10 from values like 9.5, 9.8, 9.9, the y-values approach 7
Step 3: Look at the graph of f(x) as x approaches 10 from the right side
Step 4: As x gets closer to 10 from values like 10.5, 10.2, 10.1, the y-values also approach 7
Step 5: Since both left-hand and right-hand limits approach the same value of 7, the limit exists
Step 6: Therefore, lim(x→10) f(x) = 7
- From the table:
x: 3.9, 3.99, 3.999, 4.001, 4.01, 4.1
f(x): 7.8, 7.98, 7.998, 8.002, 8.02, 8.2
lim(x→4) f(x) = ? Answer: 8 Solution: Examine the f(x) values as x approaches 4 from the left (x = 3.9, 3.99, 3.999).
Full step-by-step solution
Step 1: Examine the f(x) values as x approaches 4 from the left (x = 3.9, 3.99, 3.999).
- When x = 3.9, f(x) = 7.8
- When x = 3.99, f(x) = 7.98
- When x = 3.999, f(x) = 7.998
As x gets closer to 4 from the left, f(x) gets closer to 8.
Step 2: Examine the f(x) values as x approaches 4 from the right (x = 4.001, 4.01, 4.1).
- When x = 4.001, f(x) = 8.002
- When x = 4.01, f(x) = 8.02
- When x = 4.1, f(x) = 8.2
As x gets closer to 4 from the right, f(x) also gets closer to 8.
Step 3: Since the left-hand limit (as x→4⁻) and the right-hand limit (as x→4⁺) both approach 8, the limit exists and is equal to 8.
The answer is 8.
- A pharmaceutical company is modeling the concentration of a new medication in the bloodstream over time. The concentration function is given by C(t) = (3t^2 - 12) / (t^2 - 4) for t > 2 hours. As time continues indefinitely, what value does the drug concentration approach in the bloodstream? Answer: 3 Solution: C(t) = (3t^2 - 12) / (t^2 - 4) for t > 2. As t becomes very large, both the numerator and denominator become dominated by the highest power of t, which is t^2.
Full step-by-step solution
Let's solve this step by step.
We are given the concentration function:
C(t) = (3t^2 - 12) / (t^2 - 4) for t > 2.
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**Step 1: Identify what happens as t → ∞**
As t becomes very large, both the numerator and denominator become dominated by the highest power of t, which is t^2.
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**Step 2: Factor numerator and denominator**
Factor numerator:
3t^2 - 12 = 3(t^2 - 4)
Factor denominator:
t^2 - 4 = (t - 2)(t + 2) but we don't need the full factoring for the limit.
Actually, notice:
C(t) = (3t^2 - 12) / (t^2 - 4)
= 3(t^2 - 4) / (t^2 - 4)
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**Step 3: Simplify the function**
For t > 2, t^2 - 4 ≠ 0, so we can cancel:
C(t) = 3(t^2 - 4) / (t^2 - 4) = 3
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**Step 4: Interpret the result**
The function simplifies exactly to C(t) = 3 for all t > 2 (except at points where denominator is zero, but t > 2 avoids t = 2).
So as t → ∞, C(t) = 3 exactly.
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**Step 5: Conclusion**
The concentration approaches 3 mg/L (or whatever units) as time continues indefinitely.
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**Final answer:** 3
- Aroha is tracking the temperature of a cooling liquid in a physics experiment. She records the temperature T(t) in degrees Celsius at various times t (in minutes) using the function T(t) = (t^3 - 27)/(t - 3). The function is undefined at exactly t = 3 minutes. Using the table of values below, determine what temperature the liquid approaches as time gets closer and closer to 3 minutes.
t (minutes) | T(t) (°C)
2.9 | 26.11
2.99 | 26.9101
2.999 | 26.991001
3.001 | 27.009001
3.01 | 27.0901
3.1 | 27.91 Answer: 27 Solution: Examine the table values as t approaches 3 from the left (t < 3): - At t = 2.9, T = 26.11 - At t = 2.99, T = 26.9101 - At t = 2.999, T = 26.991001 These values are increasing and getting very close to 27.
Full step-by-step solution
Step 1: Examine the table values as t approaches 3 from the left (t < 3):
- At t = 2.9, T = 26.11
- At t = 2.99, T = 26.9101
- At t = 2.999, T = 26.991001
These values are increasing and getting very close to 27.
Step 2: Examine the table values as t approaches 3 from the right (t > 3):
- At t = 3.001, T = 27.009001
- At t = 3.01, T = 27.0901
- At t = 3.1, T = 27.91
These values are decreasing and also getting very close to 27.
Step 3: Since both sides approach the same number, 27, the limit exists. The temperature approaches 27 degrees Celsius as time approaches 3 minutes.
The answer is 27.
- From the table:
x: 0.96, 0.98, 0.99, 1.00, 1.01, 1.02, 1.04
f(x): 2.81, 2.91, 2.96, undefined, 3.06, 3.11, 3.21
What is lim(x→1) f(x)? Answer: 3.01 Solution: Examine the left-hand limit as x approaches 1 from below. The x values 0.96, 0.98, 0.99 give f(x) values 2.81, 2.91, 2.96. These are approaching 3.01.
Full step-by-step solution
Step 1: Examine the left-hand limit as x approaches 1 from below. The x values 0.96, 0.98, 0.99 give f(x) values 2.81, 2.91, 2.96. These are approaching 3.01.
Step 2: Examine the right-hand limit as x approaches 1 from above. The x values 1.01, 1.02, 1.04 give f(x) values 3.06, 3.11, 3.21. These are also approaching 3.01 from above.
Step 3: Since both the left-hand and right-hand limits approach the same value, 3.01, the limit exists.
Step 4: Therefore, lim(x→1) f(x) = 3.01.